# Description
Given an integer array nums
sorted in non-decreasing order, remove the
duplicates in-place such that each unique element appears only
once. The relative order of the elements should be kept the
same. Then return the number of unique elements in nums
.
Consider the number of unique elements of nums
to be k
, to get accepted, you need
to do the following things:
- Change the array
nums
such that the firstk
elements ofnums
contain the unique elements in the order they were present innums
initially. The remaining elements ofnums
are not important as well as the size ofnums
. - Return
k
.
Custom Judge:
The judge will test your solution with the following code:
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If all assertions pass, then your solution will be accepted.
Example 1:
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Example 2:
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Constraints:
1 <= nums.length <= 3 * 104
-100 <= nums[i] <= 100
nums
is sorted in non-decreasing order.
# 풀이
주어진 nums는 non-decresing order로 정렬이 되어있기 떄문에 idx =1
부터 시작하여 i와 i-1이 다른 숫자라면 nums[idx]에 nums[i]를 저장하여 풀이했다.
# 코드
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